a) porosity = Vp (that is Vc + Vg) /V. So, 212g - 182g = 30 g;
30g /
1g/ml (density of water) / 100ml = 30 ml/100ml = .30 = 30
%.
b) moisture content at beginning. 192 g - 182 g = 10 g or 10 ml /
100
ml = .10 = 10 %.
c) field capacity is Vc/V and Vc is the water left in the soil
that
is held by capillary action. So, in this example, the water that
remaind
after the sample was drained is what
you need to use:187g - 182 g = 5 g or 5 ml/100ml = .05 x 100% = 5%.
d) The important thing to remember here is that the volume of the
soil
has not changed, it still takes up 100 ml, but not all of that
volume is solid. So, 182 g/100 ml/(1-0.3) = 2.6
g/ml.
2) (8 points) Tensiometers are installed in a soil at 0.4 and 0.3 m above the water table in a uniform sandy soil with the moisture characteristics and hydraulic conductivity curves given in Figures 8.4 and 8.5, respectively. One set of tensiometer readings indicates that the capillary pressure head at the first of these tensiometers in -0.5m and at the second is -0.6m.
a) Make a little diagram of the set-up. Determine the hydraulic head at the two locations. Does the water flow upward or downward?
The flow is downward, because the hydraulic head decreases with depth. See graph.
b) Estimate the hydraulic conductivity in the soil and calculate the specific discharge using Darcy's law.
Moisture content from Fig 8.4
is
about 0.06. Figures
8.4 and
8.5,
can then be used to estimate hydraulic conductivity: ~10-7
m/s.
The specific discharge then is: q = -K*(Dh/Dz)
= 2 * 10-7 m/s.
3) (6 points) Unsaturated
zone
a) The infiltration rate is often
decreasing during a precipitation event. What processes
causing this behavior can you imagine? (Identify 3 of
the potential processes).
Initially the shallow layer of a dry soil takes up water very
rapidly, there is lots of pore space to be filled. A wetting front
forms and the infiltration rate is limited by how fast that front
progresses (the hydraulic conductivity is dependent on the
moisture content). Other potential reasons is that air gets
trapped below the wetting front and resists the downward flow. If
the unsaturated zone is very shallow, it could fill up completely
and infiltration could stop. Swelling of minerals as a result of
wetting could decrease the porosity as well and reducing
infiltration with time.
b) Does
this have any implications for flood forecasting?