Product: IESX

Version: 10.2

Application: Computation Manager

Search Type: FAQ


Topic:
Algorithm used for Instantaneous Frequency and how the min/max values are treated.

Description:
1) What algorithm does GeoQuest use in the instantaneous frequency calculation? 2) How are the values outside the max and min frequency window treated?


Solution:
1) fft -> zero out negative frequencies -> multiply by the quadrature trace which is derived from the Hilbert transform -> inverse fft -> THEN TAKE: (U*derivitive of V) - (V*derivitive of U)/(U^2 + V^2) then if you use weighting: SQRT (U^2 + V^2) If you use smoothing and weighting: Reflection strength * (U*derivitive of V) - (V*derivitive of U)/(SQRT U^2) 2) How this value compares to the min & max frequency value: if it is less than the min then it is set to the min if it is more than the max then it is set to the max

Last Modified on: 24-MAR-99