Product: IESX
Version: 10.2
Application: Computation Manager
Search Type: FAQ
Topic:
Algorithm used for Instantaneous Frequency and how the min/max values are treated.
Description:
1) What algorithm does GeoQuest use in the instantaneous frequency calculation?
2) How are the values outside the max and min frequency window treated?
Solution:
1) fft -> zero out negative frequencies -> multiply by the quadrature trace
which is derived from the Hilbert transform -> inverse fft -> THEN TAKE:
(U*derivitive of V) - (V*derivitive of U)/(U^2 + V^2)
then if you use weighting:
SQRT (U^2 + V^2)
If you use smoothing and weighting:
Reflection strength * (U*derivitive of V) - (V*derivitive of U)/(SQRT U^2)
2) How this value compares to the min & max frequency value:
if it is less than the min then it is set to the min
if it is more than the max then it is set to the max
Last Modified on: 24-MAR-99